98 lines
2.8 KiB
C
98 lines
2.8 KiB
C
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/*=====================================================================
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cgi例子
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=====================================================================*/
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//pass.c
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#include <stdio.h>
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#include <stdlib.h>
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#include <string.h>
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char* getcgidata(FILE* fp, char* requestmethod);
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int main(void)
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{
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char *input;
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char *req_method;
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char name[64];
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char pass[64];
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int i = 0;
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int j = 0;
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// printf("Content-type: text/plain; charset=iso-8859-1\n\n");
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printf("Content-type: text/html\n\n");
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printf("The following is query reuslt:<br><br>");
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req_method = getenv("REQUEST_METHOD");
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input = getcgidata(stdin, req_method);
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// 我们获取的input字符串可能像如下的形式
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// Username="admin"&Password="aaaaa"
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// 其中"Username="和"&Password="都是固定的
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// 而"admin"和"aaaaa"都是变化的，也是我们要获取的
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// 前面9个字符是UserName=
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// 在"UserName="和"&"之间的是我们要取出来的用户名
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for ( i = 9; i < (int)strlen(input); i++ )
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{
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if ( input[i] == '&' )
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{
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name[j] = '\0';
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break;
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}
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name[j++] = input[i];
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}
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// 前面9个字符 + "&Password="10个字符 + Username的字符数
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// 是我们不要的，故省略掉，不拷贝
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for ( i = 19 + strlen(name), j = 0; i < (int)strlen(input); i++ )
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{
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pass[j++] = input[i];
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}
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pass[j] = '\0';
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printf("Your Username is %s<br>Your Password is %s<br> \n", name, pass);
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return 0;
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}
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char* getcgidata(FILE* fp, char* requestmethod)
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{
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char* input;
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int len;
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int size = 1024;
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int i = 0;
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if (!strcmp(requestmethod, "GET"))
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{
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input = getenv("QUERY_STRING");
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return input;
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}
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else if (!strcmp(requestmethod, "POST"))
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{
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len = atoi(getenv("CONTENT_LENGTH"));
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input = (char*)malloc(sizeof(char)*(size + 1));
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if (len == 0)
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{
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input[0] = '\0';
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return input;
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}
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while(1)
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{
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input[i] = (char)fgetc(fp);
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if (i == size)
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{
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input[i+1] = '\0';
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return input;
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}
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--len;
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if (feof(fp) || (!(len)))
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{
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i++;
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input[i] = '\0';
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return input;
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}
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i++;
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}
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}
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return NULL;
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}
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